Lab 2 - ECE 421L
After creating the symbol, I predicted the delay of the DAC while driving a 10pF load. The equation I used was td≈0.7RC.
Substituting the equivalent resistance and load capacitance, td≈0.7*10kΩ*10pF => td≈70ns.
I verified this by creating this simple circuit.
After running a transient analysis, I was able to confirm my prediction. Taking into account the 10ns delay of the voltage source.
Following the creation of the symbol for my DAC, I substituted it into the original sim_Ideal_ADC_DAC.
Running a transient analysis using ADE L, I observed the graphical output.
I implemeted that circuit driving R, C, and RC loads.
Using ADE L, I ran transient analyses to observer how each load effected the output.
Using a load of 10kΩ, the output voltage is reduced by 50%. This is because with a 10kΩ resistance in series with the equivalent resistance of the DAC equates to 20kΩ. The 5V input has double the voltage drop, creating an output reduction of 50%.
Using a load of 10pF, I observed the following graphical output.
Combining these loads into, the following was presented graphically.
One thing to note; in a real circuit, the switches shown in the design guide are the outputs of the ADC. These are implemented with MOSFET transistors. The resistance of these transistors must be small in relationship to my R of 10kΩ. If the transistors resistance is close to, equal, or larger than my DAC's equivalent resistance, the input resistance to the DAC will alter the output voltage. This can give inaccurate results, which can cause problems in the real world.
Following these graphical representations in different load scenarios, I reverted to a loadless DAC to observe the effect of lowering the convergence values.
Running the simulation again with these values resulted in a less accurate graphical representation of the output.
This concluded lab 2.