Lab 2 Operation of a compensated scope probe - EE 420L 

Authored by Jeremy Garrod  

02/09/2017
Email: garrod@unlv.nevada.edu

  

Pre-Lab Work

Pre-lab work


Lab Work

Perform, and document in your html lab report, the following:



Experiment 1:
  Show scope waveforms of a 10:1 probe undercompensated, overcompensated, and compensated correctly.



                                           Undercompensated


                                               Overcompensated


                                            Properly Compensated

Experiment 2: Comment on where the type of scope probe (i.e., 1:1, 10:1, 100:1, etc.) is set on your scope (some scopes detect the type of probe used automatically).

Using the Tektronix oscilloscope that is available in the lab, you can manually set the ratio of the probe that you are using. In the menus for each scope channel there is an option called "Attenuation" that is used to select the type of scope that will be used. The probe that is used in this lab is a Tetronix 10x probe.


               10x Scope probe


                 Menu of oscilloscope showing probe type

Experiment 3:
Draft the schematic of a 10:1 scope probe showing: the 9 MEG resistor, 1 MEG scope input resistance, capacitance of the cable, scope input capacitance, and capacitance in the probe tip.


                             SPICE schematic of compensated probe

Using the values from the schematic above, the circuit was analyzed by hand to show that the output (Vout) was indeed 0.1 of the input (Vin). The output of the circuit is just a simple voltage divider between the two impedances Z1 and Z2. The first impedance, Z1, is the probe capacitor and resistor in parallel. The second impedance, Z2, is the the cable and scope capacitances added together in parallel with the resistance of the scope.


                                   Hand calculations for given schematic

Experiment 4:
 Devise an experiment, using a scope, pulse generator, and a resistor, to measure the capacitance of a length of cable. Compare your measurement results to the value you obtain with a capacitance meter. Make sure you show your hand calculations.

In order to find the capacitance of the cable, the time delay of the circuit will be used. A 100k resistor was put in series with the cable in order to stay consisent with the prelab video. When the 100k resistor is in series with the cable, the capacitance of the cable creates an RC circuit, where the time delay can be found by using t = 0.7*R*C. If a time is measured and the resistance is known (100k), the equation can be rearranged into C = t/(0.7*R), where C is the capacitance of the cable.



A time delay of 924ns was measured, which gives a capacitance of c = (924ns/(0.7*100k) = 13.2pF
In order to measure the capcitance of the cable using a capacitor meter, a pair of banana probes was used. The capcitance of the banana probes was first measured. The capacitance of the banana probes and cable were then measured together and the capacitance of the banana probes were subtracted from this value. The resulting capacitance is the capacitance of the cable.

 
                    Capacitance of the banana probes along with the cable


                             Capacitance of banana probes


0.0225nF - 0.0084nF = 14.1pF


Experiment 5: Build a voltage divider using two 100k resistors. Apply a 0 to 1 V pulse at 1 MHz to the divider's input. Measure, and show in your report, the output of the divider when probing with a cable (having a length greater than or equal to 3 ft) and then a compensated scope probe. Discuss and explain the differences.

The two scope output below are of a properly compensated scope probe and just normal cable. The output of the compensated scope probe  is larger than the cable due to the fact that the probe capacitance is in series with the other capacitances, which lowers the overall capacitance since capacitors in series work like resistors in parallel. This lower capacitance creates a lower RC time constant which means that the capacitors will charge and discharge very quickly. The output of the noncompensated cable will be much lower due to the high capacitance, which creates a large RC time constant. This in turn causes the capacitor to charge and discharge slowly. This effect can be seen by the much more linear output.



                             Output of compensated probe


                        Output of noncompensated cable

Experiment 7: Briefly discuss how you would implement a test point on a printed circuit board so that a known length of cable could be connected directly to the board and not load the circuitry on the board.


Since the cable is of a known length, the capacitance and resistance will be known values. Since these values are known, you can treat them the same way that the capacitance and resistance of the cable and scope input are treated. A resistor and capacitor that are in parallel can added into the circuit. This has the same effect that using a compensated scope probe does, it if effectively compensating the cable so that the effects are minimal.

 

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