Lab 6 - EE 420L
Authored
by Tyler Ferreira,
ferret1@unlv.nevada.edu
March 22, 2017
Pre-lab work
- This lab will utilize the ZVN3306A and ZVP3306A MOSFETs.
- Review these datasheets and become familiar with these transistors.
- Verify that the simulations seen in lab6_sims.zip reasonably model the behavior of the transistors' ID v. VGS, ID v. VDS, and gm v. VGS curves.
- Finally, watch the video single_stage_amps and review single_stage_amps.pdf
- Below are schematics for NMOS and PMOS source followers amplifiers (also known as common-drain amplifiers).
- In your lab report discuss the operation of these circuits.
- The
common-drain amplifier will have the input on the gate and the output
on the source. This means the input signal and output signal will both
be common to the drain of the transistor. The DC voltage on the gate is
found by voltage division with the power supply voltage. The NMOS DC
voltage on the source is found by multiplying the DC current by the 1k
resistor. The PMOS DC voltage on the source is found by subtracting the
voltage drop across the source resistor from the power supply voltage.
- The
AC gain of common-drain amplifiers is close to 1. It is found by
multiplying the AC current by the output resistance. The output
resistance is the output resistance of the transistor in parallel with
the 1k resistor.
- Simulate the operation of these amplifiers.
| |
NMOS
| PMOS
|
NMOS Offset
| PMOS Offset
|
- Hand
calculate, and then verify your hand calculations with experimentation
and simulations, the gains and the input and output
resistances ensuring that your test signals are at a high enough
frequency that the caps have negligible impedance but not so high that
the gain is dropping off.
Important Values | NMOS | PMOS |
Rin | 33.3k | 33.3k |
Rout | 52.9 | 86.2 |
gm | 17.9mA/V | 10.6mA/V |
Vin Operating Point | 3.33V | 1.66V |
Vout Pperating Point | 1.3V | 4.61V |
Schematic | LTspice Simulation | Experimental |
NMOS Input Resistance
| | |
NMOS Output Resistance
| | |
PMOS Input Resistance
| | |
PMOS Output Resistance
| | |
NMOS | Hand Calculations | LTspice | Experimental |
Gain | 0.947 | 1 | ~1 |
Rin | 33.3k | 33.3k | 33k |
Rout | 52.9 | 52.9 | 51 |
PMOS | Hand Calculations | LTspice | Experimental |
Gain | 0.914 | 1 | ~1 |
Rin | 33.3k | 33.3k | 33k |
Rout | 86.2 | 86.2 | 80 |
- If
you build this circuit using electrolitic capacitors, assuming the
input AC signal swings around ground, put the "+" terminal of the cap
on the gate of the MOSFET. Please indicate, in your lab report, that
you understand why the capacitor is connected this way.
- The electrolytic capacitor
is connected with the negative towards the function generator because
the AC signal has a 0V offset. The gate voltage has the 3.33V from the
voltage divider. The positive of the electrolytic capacitor should be
towards the higher potential.
- In your lab report discuss, in your own words, how to measure the input resistance.
- To
measure the input resistance of my amplifier circuit I would insert a
resistor in series with my signal generator. I would then measure the
difference in voltage over that resistor to find the current. Once I
have the current I would divide the the output voltage of the resistor by my measured current to find the input resistance.
- Again, in your lab report discuss how to measure the output resistance.
- To
measure the output resistance of my amplifier I would insert a resistor
from my output to ground. The resistor would be close to what I
calculated in my hand calculations and I would measure the output
voltage to be around half of the original voltage. If this is true that
means the resistor that I added is close to the output resistance of my
circuit since this would create a2 to 1 voltage divider.
- Below are two common-source amplifiers.
- Discuss the operation of these amplifiers in your lab report including both DC and AC operation.
- The
common-source
amplifier will have the input on the gate and the output on the drain.
This means the input signal and output signal will both be common to
the source of the transistor. The DC voltage on the gate is found by
voltage division with the power supply voltage. The NMOS DC voltage on
the drain is found by subtracting the power supply voltage by the
voltage drop across the drain resistor. For the PMOS DC voltage on the
drain it is just the DC current multiplied by the drain resistor.
| |
NMOS
| PMOS
|
NMOS Offset
| PMOS Offset
|
- Hand calculate the gains and the input/output resistances.
Important Values | NMOS | PMOS |
Rin | 33.3k | 33.3k |
Rout | 1k | 1k |
gm | 17.9mA/V | 10.6mA/V |
Vin Operating Point | 3.33V | 1.66V |
Vout Operating Point | 3.7V | 0.39V |
- How does the source resistance, Rsn or Rsp, influence the gain.
- Increasing
Rsn or Rsp will decrease the gain of the amplifier circuit. This is
because they are inversely proportional to the gain of the circuit.
- Again compare your hand calculations to simulation and experimental results.
Schematic | LTspice Simulation | Experimental |
NMOS Input Resistance
| | |
NMOS Output Resistance
| | |
PMOS Input Resistance
| | |
PMOS Output Resistance
| | |
NMOS | Hand Calculations | LTspice | Experimental |
Gain | -6.813 | -7 | -6.13 |
Rin | 33.3k | 33.3k | 33k |
Rout | 1k | 1k | 1k |
PMOS | Hand Calculations | LTspice | Experimental |
Gain | -5.4 | -5 | -1.2 |
Rin | 33.3k | 33.3k | 33k |
Rout | 1k | 1k | 1k |
- Below are two common-gate amplifiers.
- Discuss the operation of these amplifiers in your lab report including both DC and AC operation.
- The common-gate
amplifier will have the input on the source and the output on the drain.
This means the input signal and output signal will both be common to
the gate of the transistor. The DC voltage on the gate is found by
voltage division with the power supply voltage. The NMOS DC voltage on
the drain is found by subtracting the power supply voltage by the
voltage drop across the drain resistor. For the PMOS DC voltage on the
drain it is just the DC current multiplied by the drain resistor.
| |
NMOS
| PMOS
|
NMOS Offset
| PMOS Offset
|
- Hand calculate the gains and the input/output resistances.
Important Values | NMOS | PMOS |
Rin | 152.9 | 186.2 |
Rout | 1k | 1k |
gm | 17.6mA/V | 10.6mA/V |
Vin Operating Point | 3.33V | 1.66V |
Vout Operating Point | 3.7 | 0.39 |
- How does the source resistance, Rsn or Rsp, influence the gain.
- Increasing
Rsn or Rsp will decrease the gain of the amplifier circuit. This is
because they are inversely proportional to the gain of the circuit.
- Again compare your hand calculations to simulation and experimental results.
Schematic | LTspice Simulations | Experimental |
NMOS Input Resistance
| | |
NMOS Output Resistance
| | |
PMOS Input Resistance
| | |
PMOS Output Resistance
| | |
NMOS | Hand Calculations | LTspice | Experimental |
Gain | 6.19 | 6 | 5.5 |
Rin | 152.9 | 152.9 | 150 |
Rout | 1k | 1k | 1k |
PMOS | Hand Calculations | LTspice | Experimental |
Gain | 4.91 | 5 | 2.61 |
Rin | 186.2 | 186.2 | 180 |
Rout | 1k | 1k | 1k |
- Below is a push-pull amplifier.
- Discuss the operation of this amplifier in your lab report including both DC and AC operation.
- The
push pull amplifier has an inverter topology. The input signal is on
the gates of the MOSFETs and the output is on the drains of the
MOSFETs. The gain of this amplifier is controlled by the resistor
connected from the gate to the drain multiplied by the parallel
resistance of the transistors. The higher the gate drain resistor the
higher the gain will be.
- Hand calculate the gain of this amplifier.
- Do you expect this amplifier to be good at sourcing/sinking current? Why or why not?
- I expect this amplifier to be goot at both sourcing/sinking current
because the input and the output are connected to both a PMOS and an
NMOS. This means if the PMOS is turned on, the NMOS is turned off and
the circuit is good at sourcing current. When the NMOS is on, the PMOS
is off and the circuit is good at sinking current.
- What happens to the gain if the 100k resistor is replaced with a 510k resistor? Why?
- According
to my hand calculations the gain of the circuit will increase when the
gain drain resistor is increased. When testing this in the lab the gain
does indeed increase with a larger resistor.
- Again compare your hand calculations to simulation and experimental results.
Experiment with 100k Resistor | Experiment with 510k Resistor |
| |
| Hand Calculations | LTspice | Experimental |
Gain with 100k | -2.85k | -2k | 1280 |
Gain with 510k | -14.5k | -7k | 1920 |
- Note
that the gain of this amplifier is large so the output may saturate at
VDD and Ground. To avoid this saturation you can reduce the AC input
voltage using a voltage divider.
- In
the lab I setup my function generator to output 2mVpp and then
connected it to a voltage divider before connecting to the circuit. The
divider brought the 2mVpp to 1mVpp to keep the output from saturating.
I will backup my work on to my OneDrive and my desktop:
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