Lab 5 - EE 420L 

Authored by Tyler Ferreira,

ferret1@unlv.nevada.edu

March 2, 2017

  

Pre-lab work

 


Again, this lab will utilize the LM324 op-amp (LM324.pdf).

For the following questions and experiments assume VCC+ = +5V and VCC- = 0V.

 

 

 
                        I can neglect the 100k resistor because the R1/R2 ratio is much less than 1. This means R2 makes a negligible difference in our equation.
 

 
                        The circuit will not work if I remove the 100k resistor. The 100k resistor is the only feedback path for DC current, without it the output voltage will
                    go to the power rails (+5V and 0V) with a small difference between Vp and Vm. This is because of the high open loop gain of the op-amp.
 

 
                     Looking at the datasheet the LM324 has a typical open loop gain of 100V/mV or 100kV/V. Using Vout = Aol(Vp-Vm) we can see that a small
                     difference between Vp and Vm will cause the output voltage to go to the positive or negative power rails (+5V or 0V).
 
                        The 100k resistor does not have much of an effect on the frequency response because most of the AC current will flow through the capacitor
                    rather than the resistor. This is because the impedance of the capacitor is much less than the resistance of R2.
   Hand Calculations for unity-gain frequency
 
            I calculated my phase shift to be 90 degrees between my input and output.
            In my experiments my signals have about a 90 degree phase difference between them.
            My experimental phase shift is close to what I expected.



 
I decided to choose my resistor value and calculate my capacitor value. I chose a 10k resistor.
 

 
In my integrator circuit I should choose a 4.16nF capacitor and a 10k resistor. The closest capacitor I could find was a 4nF capacitor and I was able to get a 10k resistor.
 
SchematicLTspice SimulationExperimental

 
 

Design Considerations:

 

Capacitor value: I obtained this value by calculations. I would calculated what I needed and tried to find a capacitor of similar size in the lab.

 

Resistor value: I tried to choose a resistor value of 1k in order to keep the R1/R2 value negligible in my frequency response. In order to use a 1k resistor I would need a 41.6nF capacitor which I couldn't get in the lab. I decided to divide the capacitor value by 10 and multiply the resistor value by 10 to obtain my current values.

 

Input peak/min: I chose a peak of 5V and min of 0V. I chose these values because I was aiming to get a triangle wave from 1V to 4V. My input min needed to be at most 1V and my peak needed to be at least 4V. Choosing 0V and 5V made the math easier since the average was centered at my common mode voltage.
 

Input average: I wanted the average of my input to be equal to Vcm so there is little to no offset voltage.


 
I will backup my work on to my OneDrive and my desktop:

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 


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