Lab 2 - EE 420L 

Authored by Tyler Ferreira,

ferret1@unlv.nevada.edu

January 31, 2017

  

Pre-lab work


Experiment 1: Show scope waveforms of a 10:1 probe undercompensated, overcompensated, and compensated correctly.

 

10:1 Overcompensated Probe10:1 Undercompensated Probe10:1 Correctly Compensated Probe
 
Experiment 2: Comment on where the type of scope probe (i.e, 1:1, 10:1, 100:1, etc.) is set on your scope (some scopes detect the type of probe used automatically).
 

The type of scope probe is set under the channel menu. If you open up the channel menu on the scope there will be an option to change the compensation of the probe.


Experiment 3: Draft the schematic of a 10:1 scope probe showing: the 9MEG resistor, 1MEG scope input resistance, capacitance of the cable, scope input capacitance, and capacitance in the probe tip.
 
Schematic
 

 


Experiment 4: Using circuit analysis, and reasonable/correct values for the capacitances, show using circuit analysis and algebra (no approximations), that the voltage on the input of the scope probe is 0.1 the voltage on the tip.

 

Hand Calculations

 


Experiment 5: Devise an experiment, using a scope, pulse generator, and a resistor, to measure the capacitance of a length of cable. Compare your measurement results to the value you obtain with a capacitance meter. Make sure you show your hand calculations.

 

Experiment:

Image of the oscilloscope with the time delay
 

 
I measured a time delay of 744ns. Using the equation (td)/(0.7*R) = C I can find the capacitance of the cable.
       
        (744ns)/(0.7*100k) = 10.6pF
 
Using a multimeter to confirm my calculations
Capacitance of the cablesCapacitance of (cables + probe)

 
 The capacitance I calculated by doing my RC time delay experiment is off by 1pF compared to directly measuring the capacitance of the probe.
 

Experiment 6: Build a voltage divider using two 100k resistors. Apply a 0 to 1V pulse at 1 MHz to the divider's input. Measure, and show in your report, the output of the divider when probing with a cable (having length greater than or equal to 3 ft) and then a compensated scope probe. Discuss and explain the differences.

 

Uncompensated Cable10x Compensated Cable
 
Channel 1 (Yellow): Input signal
Channel 2 (Blue): Output signal
 
Measuring the output voltage with the uncompensated probe results in a larger time delay and higher voltage.
By using the 10x compensated probe my voltage will be 0.1 times the input voltage and the time delay will be lower due to less capacitance.
 

Experiment 7: Finally, briefly discuss how you would implement a test point on a printed circuit board so that a known length of cable could be connected directly to the board and not load the circuitry on the board.

  

To implement a test point on a PCB we could design the circuit to include a capacitor and resistor in parallel at this point. By having a resistor in parallel with a capacitor at the test point it will turn the uncompensated probe into a compenstaed probe, therefore allowing the cable to connect directly to the board without loading the circuitry.

 


 

I will backup all of my work on to my OneDrive and my Desktop.

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 


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