Lab 2 - EE 421L
Design of a 10-bit digital-to-analog converter (DAC)
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POST LAB:
Our DAC follows the design of the schematic below.This is the bottom layer after descending all the way down to the schematic of our primitive sections of my DAC.
Ascending up a layer, we can see the DAC Bit symbols interconnected with one another creating the B[9:0] input to our DAC.
Ascending another layer up, we can see the final schematic all put together utilizing our new DAC, including the new symbol.
In order to obtain our total output resistance, we underwent the below calculations. After combining all subsections of our new schematic through our iterative process, we obtain an overall resistance of R, which equals 10kohms.
Calculating the delay to the circuit
We verfified this calculations through our simulation by grounding all of the inputs of the DAC except for b9. After, we connected a 1V amplitude pulse source to b9, and a 1 pF capacitor load was utilized as well.
This simulation verifies our 70ns when the output is 50% of the max value.
This is the simulation results of our new schematic. Again, the sine wave analog input closely follows the analog output of our new DAC we created.
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DRIVING LOADS
This the schematic of us testing our system with a 10k resistor load.
This is the simulation result of us testing our testing with ONLY a 10k resistor load. We can observe that our output is now half of its original amplitude. This is due to the resulting voltage divider between the output resistance of the DAC (10kohms) and the 10kohms load resistance.
This is the simulation result of testing our capacitor load by itself.
This is the schematic of our resistor and capacitor load added to our system.
If the resistance of the switches is not small compared to R, then the input signal of the DAC would be a lot smaller.
Conversely, better results are obtained when the resistance of the switches is smaller compared to R, so Vout closely follows Vin.