Lab 2 - ECE 421L
Escoba3@unlv.nevada.edu
September 13th, 2017
Design of a 10-bit DAC using an n-well R of 10k
This design follows what was generally expected except I place a 2R valued resistor instead of 2 R sized resistors in series.
How to create a symbol view for your design
With the above n-well constructed, we can create a symbol to make it much easier to view in a large circuit. By selecting Create -->Cellview-->From Cellview, we should get something like this;
Determining the total output resistance of the DAC
When two resistors are placed in parallel of the same value, the result will be a new total resistance of half the orginal. This idea actually works itself here as the last two resistors are 2R//2R, which would equal R. That R is in series with another R, thus again creating a 2R. This process repeats which results in the final output resistance being R alone.
Delay, driving a load.
If we use the formula 0.7RC to predict the delay of a DAC in this manner, we should expect the following;Simulations to verify your design functions correctly
Now, I will use the DAC I recreated to replace the Ideal DAC in the orginal schematic, below represents my new schematic
When I simulate this, I received the following
Which nearly represents what we saw with the ideal DAC, the difference being a start up time in the beginning of the output signal
Simulation when driving a 10k load
With this, we can clearly see a phase shift in the output voltage
Simulation with an RC Load
With this, we can see both a phase shift and a reduction in output voltage
Real Circuit considerations
In a real circuit, the resistance of the switches may not be small compared to the value of R, in such a case, the voltage on the output will be smaller as the resistance in series will be taken up more by the input resistance.
Backing up files