Lab 6 - EE 420L 

Authored by Jacob Reed

reedj35@unlv.nevada.edu

Due Date: March 27, 2019

  

For this lab, we will be looking at single-stage transistor amplifier circuit topologies and how they operate.

There will be 4 experiments where each focus on a specific topology for both an NMOS and PMOS. The

specific MOSFETs we will be experimenting with are ZVN3306A and ZVP3306A.

 

Experiment 1: Source Follower (Common-Drain Amplifier)

 

Figure 1: Source Follower Schematic

Circuit Operation:

This circuit is known as either a source follower or common-drain amplifier. The reason why it’s called a common-drain

amplifier is because the drain is common to both the input and output of the MOSFET. The gate of the MOSFET is the

input, and the source is the output. This leaves the drain common to both. This circuit will have an approximate gain of

1 due to its topology. There will be a DC voltage at the gate found by voltage division due to R1 and R3. This voltage

division is to ensure that the MOSFETs are in saturation. The capacitor is a coupling capacitor for AC coupling so that the

biasing is not affected. This circuit is normally used as a voltage buffer.

 

ZVN3306A DC Calculations:

Looking at the “models_3306.txt” file,

,   

 

ZVN3306A AC Calculations:

 ,

 

ZVP3306A DC Calculations:

Looking at the “models_3306.txt” file,

,   

 

ZVP3306A AC Calculations:

 ,

 

Using Electrolytic Capacitors:

For these circuits, 15µF capacitors (10µF was not readily available) were used. The reason why the capacitors

must be connected in a specific way is because these capacitors are polarized. Since Vin is a small signal that

is generated by the function generator, that node in the circuit has a DC voltage of 0. The gate of the MOSFETs

will have a higher DC voltage at the gate of the MOSFET than at the small signal input coming from the function

generator. The capacitors are polarized, meaning that the higher DC potential of the circuit should be getting

the “+” terminal of the capacitor and the “-“ terminal should be attached to a node that is at a lower potential.

This is due to the material inside of the capacitor that allows the capacitor to charge when there is an electric

field present. There is a specific magnitude of electric field that will cause the material to break down, known as

EBD when the field applied is in the correct direction. If the field applied is in the incorrect direction, the material

will break down differently than designed, and the capacitor could fail to operate correctly.

 

 

Simulations:

Figure 2: DC Calculations

Figure 3: Spice Error Log

 

Figure 4: Waveforms to determine gain

 

Figure 5: Schematic with Input Resistance

Figure 6: Input Resistance simulation at 10kHz

Figure 7: Schematic with Output Resistance

Figure 8: Output Resistance simulation at 10kHz

 

Experimental Measurements:

NMOS

PMOS

Figure 9: ZVN3306A Gain - Input:Yellow, Output:Blue

Figure 10: ZVP3306A Gain - Input:Yellow, Output:Blue

Figure 11: Voltage drop across Rin for ZVN3306A

Figure 12: Voltage drop across Rin for ZVP3306A

Figure 13: Voltage drop across Rout for ZVN3306A

Figure 14: Voltage drop across Rout for ZVP3306A

Figure 15: Vgs calculation - Vg:Yellow, Vs:Blue

Figure 16: Vsg calculation - Vs:Yellow, Vg:Blue

 

To measure the input resistance, one would just place a resistor equivalent in value to the

calculated input resistance into the circuit in between the input signal and capacitor. Find

the voltage drop across the resistor and divide by the value of the resistor to find the current

that flows through the resistor. You then find the peak voltage at the node between the resistor

and capacitor. Divide the peak voltage found by the current that flows through the resistor

to find the experimental value of input resistance. For this experiment, the blue waveform

in figures 11 and 12 also show the peak voltage at the node between the resistor and capacitor.

 

ZVN3306A Input Resistance Measurement:

 

ZVP3306A Input Resistance Measurement:

 

To measure the output resistance, one would use a resistor equivalent in value to the calculated

output resistance in series with a large capacitor. These two would be placed in parallel to the resistor

that shares a node with the output. Find the current that flows through this resistor, and measure the

peak voltage at the gate and source of the MOSFET to find vgs. Divide vgs by the current that flows

through the resistor to find the output resistance.

 

ZVN3306A Output Resistance Measurement:

 

ZVP3306A Output Resistance Measurement:

 

ZVN3306A:

 

Gain (V/V)

Rin (Ω)

Rout (Ω)

Hand Calculations

0.948

33.3k

52

Simulations

0.948

33.3k

56

Experimental

0.964

35.3k

67

 

ZVP3306A:

 

Gain (V/V)

Rin (Ω)

Rout (Ω)

Hand Calculations

0.914

33.3k

86

Simulations

0.903

33.3k

86

Experimental

0.679

44.1k

63

 

Experiment 2: Common-Source Amplifier

 

Figure 17: Common-Source Amplifier Schematic

Circuit Operation:

Unlike the common-drain amplifier, this common-source amplifier has the input at the gate and the output at the drain.

This means that the source is common between the input and the output. Just like before, the voltage divider at the gate

ensures that the MOSFETs are in saturation, and the capacitor is for AC coupling. The gain for this device can be increased

or decreased by changing the value of Rsn and Rpn. We will see in the hand calculations and experiment that increasing

the value of these resistors will decrease the gain of the amplifier.

 

ZVN3306A DC Calculations:

Looking at the “models_3306.txt” file,

,   

 

ZVN3306A AC Calculations:

 

 

 ,

 

ZVP3306A DC Calculations:

Looking at the “models_3306.txt” file,

,  

ZVP3306A AC Calculations:

 

 

 ,

 

Simulations:

Figure 18: DC Calculations

Figure 19: Spice Error Log

 

Figure 20: Waveforms to determine gain

 

Figure 21: Schematic with input resistance

Figure 22: Input resistance simulation at 10kHz

Figure 23: Schematic with output resistance

Figure 24: Output resistance simulation at 10kHz

 

Experimental Measurements:

NMOS

PMOS

Figure 25: ZVN3306A Gain - Input:Yellow, Output:Blue

Figure 26: ZVP3306A Gain - Input:Yellow, Output:Blue

Figure 27: Rsn increased to 200, gain has decreased

An increase in Rsp will result in the same decreased gain as with the NMOS.

Figure 28: Voltage drop across Rin for ZVN3306A

Figure 29: Voltage drop across Rin for ZVP3306A

Figure 30: Voltage drop across Rout for ZVN3306A

Figure 31: Voltage drop across Rout for ZVP3306A

Figure 32: Vgs calculation - Vg:Yellow, Vs:Blue

Figure 33: Vsg calculation - Vs:Yellow, Vg:Blue

 

ZVN3306A Input Resistance Measurement:

 

ZVP3306A Input Resistance Measurement:

 

ZVN3306A Output Resistance Measurement:

 

ZVP3306A Output Resistance Measurement:

 

ZVN3306A:

 

Gain (V/V)

Rin (Ω)

Rout (Ω)

Hand Calculations

-6.51

33.3k

1k

Simulations

-6.82

33.3k

1k

Experimental

-4.6

37.6k

145

 

ZVP3306A:

 

Gain (V/V)

Rin (Ω)

Rout (Ω)

Hand Calculations

-5.17

33.3k

1k

Simulations

-5.38

33.3k

1k

Experimental

-1.92

37.9k

560

 

Experiment 3: Common-Gate Amplifier

 

 

Circuit Operation:

Just like the two circuits beforehand, this topology also has a node in common with the input and output.

The node that is in common with the input and output is the gate; hence why it is called a common-gate

amplifier. A small signal is applied at the source of each MOSFET and the output is at the gate. This circuit

will have a similar gain as the common-source amplifier, however, the output will not be inverted. In other

words, the output will not have a phase shift. We will see this in simulation and in the experiments; also,

the fact remains the same with Rsn and Rsp in that when increased, gain decreases.

 

ZVN3306A DC Calculations:

Looking at the “models_3306.txt” file,

,   

 

ZVN3306A AC Calculations:

 

 

 ,

 

ZVP3306A DC Calculations:

Looking at the “models_3306.txt” file,

,  

ZVP3306A AC Calculations:

 

 

 ,

 

Simulations:

Figure 34: DC Calculations

Figure 35: Spice Error Log

 

Figure 36: Waveforms to determine gain

 

Figure 37: Schematic for input resistance

Figure 38: Input resistance calculation for ZVN3306A

Figure 39: Input resistance calculation for ZVP3306A

Figure 40: Schematic for output resistance

Figure 41: Output resistance calculation for both MOSFETs

 

Experimental Measurements:

NMOS

PMOS

Figure 42: ZVN3306A Gain - Input:Yellow, Output:Blue

Figure 43: ZVP3306A Gain - Input:Yellow, Output:Blue

Figure 44: Rsn increased to 200Ω, gain has decreased

An increase in Rsp will result in the same decreased gain as with the NMOS.

Figure 45: Voltage drop across Rin for ZVN3306A

Figure 46: Voltage drop across Rin for ZVP3306A

Figure 47: Voltage drop across Rout for ZVN3306A

Figure 48: Voltage drop across Rout for ZVP3306A

Figure 49: Output is approx half of the original output

 

ZVN3306A Input Resistance Measurement:

 

ZVP3306A Input Resistance Measurement:

 

ZVN3306A and ZVP3306A Output Resistance Measurement:

In figure 49, we can see that the output of the MOSFET is half that of the original gain

of the MOSFET. This shows that the output resistance is indeed, 1kΩ.

 

ZVN3306A:

 

Gain (V/V)

Rin (Ω)

Rout (Ω)

Hand Calculations

5.86

162

1k

Simulations

6.10

153

1k

Experimental

4.29

323

1k

 

ZVP3306A:

 

Gain (V/V)

Rin (Ω)

Rout (Ω)

Hand Calculations

4.66

196

1k

Simulations

4.82

189

1k

Experimental

1.5

466

1k

 

Experiment 4: Push-Pull Amplifier

 

 

Circuit Operation:

A push-pull amplifier is meant to source current to a load and sink current from a load. The resistor serves to self-bias the circuit

and no DC current will flow through the MOSFETs. When there is a small signal input, the positive cycle will turn on M1 and turn

off M2; and on the negative cycle M1 will be off and M2 will be on. It seems that this circuit will serve as a sink and source for the

load and provides large amplification, and as such, large power output.

 

Circuit Calculations:

 

Do you expect this amplifier to be good at sourcing/sinking current? Why or why not?

I expect this amplifier to be good at both sourcing and sinking current. When one of the MOSFETs is turned

on, the other one is off. An NMOS is good at sinking current and a PMOS is good at sourcing current.

Since this is the case, the NMOS will be on and good at sinking current while the PMOS is off and vice versa.

 

What happens to the gain if the 100k resistor is replaced with a 510k resistor? Why?

According to my hand calculations, the gain will increase when the 100k resistor is increased to a larger value.
An increase in value of the resistor will force the gain to also linearly increase.

 

Simulations:

 

 

Figure 50: Gain with input of 0.5mV (due to voltage division) for 100k resistor

Figure 51: Gain with input of 0.1mV (due to voltage division) for 510k resistor

 

 

Gain (V/V) of 100k

Gain (V/V) of 510k

Hand Calculations

2.9k

14.6k

Simulations

1.99k

3.46k

Experimental

1.28k

11.2k

 

For the simulation of the gain with a resistance of 510k, the simulation looks like it is saturated

at the peak and so the simulation could not correctly display what the actual gain is. 

 

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