Lab 3 - EE 420L
reedj35@unlv.nevada.edu
Prelab Work
Lab Description
The following
questions are based off of the data sheet for this
op-amp.
For the following
questions and experiments assume VCC+ = +5V and VCC- = 0V.
1. Knowing the non-inverting
input, Vp, is at the same potential as the inverting
input, Vm, (called the common-mode voltage, VCM) what
are the maximum and minimum allowable common-mode voltages?
As seen from the datasheet below, at an ambient temperature of
25ºC (77ºF ~ roughly room temperature), the minimum allowable VCM is 0V and the
maximum allowable VCM is VCC – 1.5V which is 5V-1.5V = 3.5V. In
summary, VCM,
allowable min = 0V and VCM, allowable max = 3.5V.
Figure 1: LM324 Electrical Characteristics of common-mode voltage
2. What is a good estimate for
the op-amp's open-loop gain?
Based off of the table and images below
we can make a decent estimate for the op-amp’s open loop gain. Let us first
look at Figure 3 and notice that the open loop frequency response plot shows
that there is a gain of 100dB at a frequency of 10Hz. The voltage gain plot
(Figure 4) shows that at VCC = 5V, there is a gain of approximately
100dB. The large signal voltage gain plot (Figure 5) shows that at an ambient
temperature of 25ºC, there is a gain of approximately 109dB. Finally, looking
at the electrical characteristics (Figure 2), we are told that there is a gain
of 100V/mV (100 x 103 = 100,000) at 25ºC. Taking the approximate
value of 100dB from the plots, we know: As such, and Therefore, I believe a good estimate for this
op-amp’s open- loop gain is: AOL
= 100,000.
Figure 2: LM324 Electrical Characteristics of Large Signal Voltage Gain
Figure 3: LM324 Open Loop Frequency Response (100dB gain @ 10Hz) |
Figure 4: LM324 Voltage Gain (100dB gain @ 5V VCC) |
Figure 5: LM324 Large Signal Voltage Gain (~109dB gain @ 25ºC) |
3.
What is a good estimate for the offset voltage? For worst case design what value would you use?
As we can see from the
electrical characteristics for the input offset voltage (Figure 6) below, at an
ambient temperature of 25ºC, there is a typical offset voltage of 2mV and a max
of 5mV. Therefore, a good
estimate for the offset voltage is 2mV. For worst case design, I would use 9mV as my offset
voltage to consider ambient temperatures that are either very low or
very high.
Figure 6: LM324 Input Offset Voltage Parameter
Build, and test,
the following circuit
Figure 7: First op-amp circuit
1. What is the common-mode voltage, VCM? Does VCM change? Why or why
not?
By looking at the
circuit on the bottom, we can see that it is a DC circuit. This means that we
can treat the capacitors as “open” in the circuit and see that it is a simple
voltage divider where VCM is just half of VCC. Therefore,
VCM = 2.5V.
VCM does not change because VCC does not change and
neither do any of the circuit components.
Figure 8: Common-mode voltage of approximately 2.6V
2. What is the ideal closed-loop gain?
The ideal closed-loop
gain is easy to calculate. This is a simple inverting topology of an op-amp and
treating it as ideal means no current flows in or out of Vm
or Vp. We know that an inverting
op-amp topology has a gain of: Since both resistors are
the same value, then that means we will have an ideal closed-loop gain of -1. For a sinusoid, this
means that the output signal is going to be equal in amplitude but 180º out of
phase.
3. What is the output swing and what is it centered around?
As seen below through
simulation and experiment, the output swing is 100mV and it is centered around
2.5V. The reason why the amplitude is 50mV in Figure 12 is because we had the
oscilloscope set to 50Ω output and so it cut the output in half. Figure
11 shows how the circuit was set up on a breadboard. Looking at Figure 13, we
can see the waveforms with DC Coupling. Noticing that the “zero” for each
waveform is at a different height on the horizontal axis, this means that the
waveforms are not exactly swinging around the same voltage. I believe this is
due to the long wires I used with the building of the circuit; picking up noise
from everything in the room. This threw the output off from swinging around
2.5V.
Figure 9: LTSpice
implementation of circuit |
Figure 10: Resulting waveform of LTSpice simulation |
Figure 11: Breadboard implementation |
Figure 12: Input (yellow) and output
(blue) voltage (AC Coupling) |
Figure 13: Input (yellow) and output (blue) voltage (DC Coupling) |
3.1. What
happens if the input isn't centered around VCM, that is, 2.5 V?
If the input is not centered around the same
voltage as VCM, we see below that the output signal is no longer the
same as the input and out of phase. If the input is either above +VCC or
below -VCC then it will clip because the VCC rails of the
op-amp are what sets the maximum and minimum voltages of the output; which
means that it will limit the gain as well, depending on what VCC is
set to. Below, I simulated the input with a DC offset of 2.7V and we can see
that the two signals are separated with VCM = 2.5V.
Figure 14: DC offset of input signal set to 2.7V
3.2. Provide a
detailed discussion illustrating that you understand what is going on.
As seen from the above
simulation images and experimental images, it becomes easier to see how an
op-amp basically operates. With the input’s DC offset equal to VCM
and Rf = Ri, there will be an ideal closed-loop gain of
-1. As the DC offset is swept above or below VCM, then the input and
output waveforms will separate, and the output waveform will not swing around VCM
as it should. Also, if the input has a DC offset that brings the output swing
to be above +VCC or below -VCC, then the waveform will be
clipped due to VCC limiting how high the voltage may go in the
op-amp.
4. What is
the maximum allowable input signal amplitude? Why?
The maximum allowable
input signal amplitude for this circuit is 2.5V. This is because the DC offset
of the signal is 2.5V, +VCC = 5V, and -VCC = 0V. With an
AC signal riding the DC, that means with an amplitude of 2.5V it will go above
and below the 2.5V offset by 2.5V. This means its peak voltage will be 5V and its
minimum voltage will be 0V. If the signal amplitude were any higher, then we
would see it clipping.
5. What is
the maximum allowable input signal if the magnitude of the gain is increased to
10? Why?
If the gain is increased
to 10, then we would have and This means that to keep the
output the same, the input will have to be 1/10th the output.
Therefore, if 2.5V is our output,
6. What is
the point of the 0.01 µF capacitors from VCC and VCM to ground?
The purpose of the 0.01
µF capacitors from VCC and VCM to ground are as
decoupling capacitors. These capacitors serve to remove noise from other
circuit elements by absorbing their signals and allowing them to discharge.
6.1. Are these
values critical or could 0.1 µF, 1,000 pF, 1 µF, etc. capacitors be used?
These values are not
critical since we are dealing with a DC voltage for VCC and act as
an open in the circuit. Either 0.1 µF, 1,000pF, or 1µF capacitors could be
used.
7. The data
sheet shows that this op-amp has an input bias current that flows out of the
op-amp's inputs of typically 20 nA. This current flows
out of both the non-inverting and inverting inputs through the resistors
connected to these inputs. Show how the
operation of the circuit can be affected if, for example, R1 and R2, are much
larger. Explain what is going on.
If R1 and R2 were much
larger, then even a small current like 20nA could cause a significant voltage drop across them and our VCM will change. For
example, if we ignore VCC and it becomes a short, then there are two
10k resistors in parallel. Their equivalent resistance comes out to be 5kΩ
and the voltage drop is This voltage is added to VCM
and will clip the output since we only have a maximum allowable signal
amplitude of 2.5V. With the smaller resistors that we are using, however, is
not a problem. When resistors in the MΩ (106) or GΩ (109)
range are used, then there will be a significant voltage drop and the output of
the op-amp will suffer clipping at the VCC value.
7.1. What is
the input offset current? What does this term describe?
The input offset current describes the current
that is the difference between the input bias currents of the op-amp terminals.
These biasing currents flowing out of the non-inverting and inverting inputs
are averages values. These biasing currents make it so current does not flow
into the terminals and the difference between the currents that flow out of
these terminals is called the input offset current.
Explain how the following circuit can be used to measure the op-amp's
offset voltage
Figure 15: Second op-amp circuit
We can see in
this circuit that the inverting terminal is connected to VCM with a
1kΩ resistor in series and that the non-inverting terminal is also
connected to VCM. If we can assume that it is an ideal op-amp, then Vm = VCM, and there is no current
flowing through the 1kΩ resistor. In this circuit, there is a gain of 20.
When we find the difference between the output voltage and the common-mode
voltage, we can divide that number by the gain to find our experimental offset
voltage. The calculation to find the offset voltage is as follows:
Measure the offset voltage of 4 different
op-amps and compare them
For the following offset voltage measurements, I
used Rf = 100kΩ and Ri = 1kΩ. Therefore, the
ideal closed-loop gain, AV, is 100.
Figure 16: LM324 Breadboard implementation |
Figure 17: LM324 Offset Voltage Measurement
|
Figure 18: LM348 Breadboard implementation |
Figure 19: LM348 Offset Voltage Measurement
|
Figure 20: LM339 Breadboard
implementation |
Figure 21: LM339 Offset Voltage Measurement
|
Figure 22: LM393 Breadboard
implementation |
Figure 23: LM393 Offset Voltage Measurement
|
Conclusion
This lab proved
to be an incredibly useful tool to learn about op-amps. We were able to look at
how these devices are theoretically supposed to work; even under ideal (AOL
= ∞) and non-ideal (AOL = finite) conditions. I have become
more accustomed to looking at and understanding the datasheet for an op-amp as
well. Although this lab only covered a few of the electrical characteristics of
an op-amp, it was interesting to see how to measure offset voltage of the
device by simple circuit manipulation. The input offset voltage could affect
the output only slightly, but still affect it nonetheless and throw off
measurements. Other things that may be difficult to measure, such as input bias
current, can be analyzed by a thought experiment. As designers, we are more
well-equipped on how to control what is a desired output of the op-amp by
knowing its output swing and maximum allowable input amplitude to ensure there
is no unwanted voltage clipping.
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