Final Project - EE 420L
reedj35@unlv.nevada.edu
Lab Report
In order to begin this project, we needed to decide
what type of amplifier topology to use that would give us a good amount of
gain. The first amplifier type that comes to mind is the push-pull amplifier.
From Lab 6, we know that the push-pull amplifier can provide the designer with
a large amount of gain. This will be my starting point for the project.
Simulation and Theory
I will show the final design of the amplifier
and explain the design considerations for the amplifier.
Figure 1: Amplifier Design
The results of the performance for the
amplifier are as follows:
Figure 2: Gain of 10.23 @ 100Hz |
Figure 3: Input Resistance of
~1.8MHz @ 100Hz |
Figure 4: I(VDD) of 0.602mA showing
current draw from power supply |
Figure 5: Output Swing of
approximately 4.5V |
Figure 6: Rolloff
frequency at 584.8kHz |
|
Figures 2-3 above show that the amplifier meets the requirements of a voltage gain of 10.23, input resistance of 1.8MHz, and a current draw of 0.602mA, respectively.
The
resistor, R1, is chosen to have such a high value because it needs to be much
higher than the resistance of the load. Therefore, I chose 20MΩ. There is a large
capacitance
placed at the gates of the MOSFETs, and as such, the input signal is passed to
the gates of the MOSFETs. If resistors are placed at the sources of each
MOSFET, we
can limit the current draw; which is desirable for the quiescent current draw
design constraint. The values of the resistors in the final design were chosen
due to
real-life laboratory conditions, and these resistances are what helped the
amplifier meet specification.
To show the
hand calculations for these resistor values, I will do the following (for a
current draw of 0.6mA):
From Lab 6,
I know that KPN = 0.1233 and KPP = 0.145.
For the
final design, I ended up using a resistance of 6.75kΩ. Using circuit analysis, I can solve
for the gate voltage of both MOSFETs.
Now I can
solve for the source voltage of the PMOS.
Now that
this has been found, I can find what kind of resistance is needed at the source
of the PMOS in order to keep the current draw at 0.6mA.
This value
is very close to the resistor needed which was 70Ω.
Another
thing to note in the simulation schematic is that the 12pF capacitors at the
input and output of the circuit are to model the scope probes used.
The 100µF
capacitor in parallel with the 6.75kΩ resistor is to help with the gain
of the amplifier while not affecting the quiescent current draw. The 200Ω
resistor is
chosen because it is small when compared to the large capacitor, so that the
time constant is not very high, but the capacitor effectively remains
a short so
the resistor, R4, helps control the gain.
From Lab 6,
gmn = 18.04 mA/V and gmp
= 10.6 mA/V.
The
theoretical gain of the designed amplifier is
There is a
small, yet acceptable difference between the theoretical hand calculation and
theoretical simulation.
For the
input resistance,
Experimental Measurements
Circuit
Setup
Figure 7: Circuit on a breadboard
I will show
the operation and performance of this amplifier below.
Figure 8: Gain of amplifier at 100Hz |
Figure 9: Output swing of
approximately 5V |
Figure 10: Rolloff
frequency of approximately 580kHz |
Figure 11: Quiescent Current Draw |
|
|
The
screenshots above show the gain, output swing, rolloff
frequency, and quiescent current draw. The rolloff
frequency is important to show so that we can observe
the speed
of the amplifier. The reason why this is important is because it limits the
input frequency that can be applied to the circuit, and is helpful to the
circuit designer
so that
they know if the amplifier is the best choice for their project. The same can
be said about the output swing; it keeps the designer is aware of the
limitations as far
as how much
of a DC offset, or how high of an amplitude can be applied to the input of the
amplifier.
For input resistance,
I added a resistor of 180k to the input of the amplifier, and then measured the
voltages on either side to determine the voltage drop. From that voltage
drop, I can
divide it by the value of the resistor to get the input current, Iin. Once the input current is measured, I can
divide the input voltage by the input current and that
will give
me the input resistance.
Figure 12: Voltage (V1) at one side
of the 180k resistor |
Figure 13: Voltage (V2) on the other
side of the 180k resistor |
Parameter |
Hand
Calculations |
Simulation |
Experimental |
Gain (V/V) |
-15.75 |
-10.23 |
-10.3 |
Input Resistance (MΩ) |
1.82 |
1.8 |
1.799 |
Quiescent Current Draw (mA) |
0.6 |
0.602 |
0.885 |
Rolloff
Frequency (kHz) |
|
584.8 |
580 |
Conclusion
In conclusion,
this project was perfect as the culmination for the students to experiment with
the design of an amplifier given constraints. The simulations and hand
calculations
match the
experiments well, and that was satisfying as a designer. It was a difficult
task in the beginning, but I was able to design an amplifier within the given
design constraints,
and I feel
I am a better circuit designer because of it.